A particle is in motion along a square path ABCD of side length 10 meters. If it starts at point A and reaches point C. What is the magnitude of the displacement of the particle?
A
10 m
B
20 m
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
The points A and C are diagonally opposite each other in the square. Therefore, the displacement is the length of the diagonal of the square.
Using the Pythagorean theorem,
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle is moving with velocity 5 m/s towards east and its velocity changes to 5 m/s north in 10…
The displacement-time relationship for a particle is given by . The acceleration of the particle is
A particle has velocity given by v = 20 + 0.1 t 2 then it has
The displacement is given by x = 2t 2 + t + 5, the acceleration at t = 5 sec will be
A particle is moving so that its displacement is given as meter. Its velocity at the instant when …
If velocity of a particle is given by . The average acceleration between 2 and 5 s is